Test group description
The scenario is a corridor 4 m wide and 50 m long, with an exit at one end. A door with a registering device is located in the middle of the corridor. There are such a number of people in the corridor to the left of the door to provide a flow density equal to 0.9 m^2⁄m^2 . The start time for all people is zero.
The traffic intensity in the doorway can be calculated using the formula:
$$ q = \frac{Nf}{t\delta} (1)$$
where N is the number of people who passed through the door, δ is the width of the door, t is the time for which people passed, f is the area of the horizontal projection of a person.
A typical graph of people passing through the doorway in this group of tests has the form shown in Figure 2.
In determining the number of people and the time for them to pass through the doorway, a linear section is considered where the flow density can be assumed to be greater than 0.9 m^2⁄m^2 .
Expected results
The traffic intensity in the doorway at a flow density of 0.9 m^2⁄m^2 or more equal to 8.5 m/min is set for a doorway width of 1.6 m or more, and for a doorway of less width, the traffic intensity should be determined by the formula:
$$ q = 2,5 + 3,75 ⋅ δ (2)$$
The dependence of the traffic intensity in the doorway on the width of the doorway must be in accordance with relationship (2).
Modeling results
Figure 3 shows the results of the simulated motion in the doorway for doorway widths from 0.7 m to 2.0 m.
Analysis of the results
Figure 3 shows that the intensity of human traffic in the doorway corresponds well to relationship (2).